Given a list containing integers, find the largest positive integer that its negative also exists in the list.

Intuition

There are two ways to solve the problem.

• One way is to use two sum, we find the all pairs of integers such that their sum is zero and the one is the negative of the other.
• The second way is to use two pointer, we move left and right pointer utils their absolute values are equal.

Approach 1: two sum

Similar to Two Sum, for each num in nums, we store its negative -num in the hash table, however, notice that the added term can be determined by num, we can use a set instead.

Complexity

• $$O(n)$$
• $$O(n)$$

Code

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class Solution {
public:
    int findMaxK(vector<int>& nums) {
        set<int> s;
        int result = -1;
        for (int num: nums) {
            if (s.find(-num) != s.end()) {
                result = max(result, abs(num));
            } else {
                s.insert(num);
            }
        }
        return result;
    }
};

Approach 2: two pointer

We first sort the lists, then we use left=0 and right=length(nums) pointer to iterate the list, there are three cases:

1. if nums[left] == -nums[right], then we directly return nums[right] since this is the largest one (note that the list is sorted)
2. if nums[left] < -nums[right], then we update left to left + 1 since (nums[left], -nums[left]) cannot be found in the list.
3. if nums[left] > -nums[right], then we update right to right - 1 since (-nums[right], nums[right]) cannot be found in the list.

Complexity

• $$O(n\log n)$$
• $$O(1)$$

Code

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class Solution {
public:
    int findMaxK(vector<int>& nums) {
        sort(nums.begin(), nums.end());
        int left = 0, right = nums.size() - 1;
        while (left <= right) {
            if (nums[left] == -nums[right]) return nums[right];
            else if (nums[left] < -nums[right]) ++left;
            else --right;
        }
        return -1;
    }
};
``

# References
- [Leetcode](https://leetcode.com/problems/largest-positive-integer-that-exists-with-its-negative/description/)
- [Leetcode Two Sum](https://leetcode.com/problems/two-sum/)